How to take the 8th bit in lsb
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I am applying LSB for image steganography and I have got the binary representation of an rgb image i. e. 10001010 but I m not getting any idea of how to use the 8th bit to hide data in it anybody plz help me.
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Jan
el 31 de Mayo de 2018
The readers cannot guess, what "binary representation of an rgb image i. e. 10001010" exactly is. Is this a logical vector, a decimal number or a character vector? Did you search in the forum for "lsb steganography" already? You will find a lot of corresponding threads.
I strongly recommend to remove the "ASAP" from the question. Pushing the readers is counterproductive, because it sounds impolite.
Respuestas (1)
Walter Roberson
el 1 de Jun. de 2018
You can use bitset() and bitget() .
To extract the lsb you can use mod(YourImage,2) . To set new lsb you can do
YourImage - mod(YourImage,2) + NewLSBValue
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