make C code to be a matlab code about LCM, please help me

here is the C code

 #include <stdio.h>
int main()
{
int m, n, a, b, t, hc, lc; // variable declaration
printf(" Enter two numbers: ");
scanf("%d%d", &a, &b);
    m = a;
    n = b;
    while (n != 0)
    {
    t = n;
    n = m % n;
    m = t;
    }
    lc = (a*b)/hc; // lcm
    printf(" The Least Common Multiple of %d and %d = %d\n", a, b, lc);
    return 0;
}

then here is my matlab code

 clear all; close all; clc; 
a = input('first number = ')
na = numel(a);
b = input('second number = ')
nb = numel(b);
m = na;
n = nb;
while n~=0
    t =n;
    n =mod(m,n);
    m =t;
end
lcm = na*nb/m;
fprintf('lcm is %d.', lcm);

please help correct me if I'm wrong

Answer 1

[Guillaume]

if I'm wrong

Why can't you find that out yourself by testing your code with a few different values?

Have a look at the documentation of numel. Does it do what you meant it to do? Note that input the way you use it already returns a numeric value, so there's nothing special to do to a or b.

Answer 2

[Ankita Bansal]

Hi, numel(a) returns number of elements in a vector or matrix a. Remove the lines na=numel(a) and nb=numel(b) and modify your code to

clear all; 
close all; 
clc;
a = input('first number = ')
b = input('second number = ')
m = a;
n = b;
while n~=0
    t =n;
    n =mod(m,n);
    m =t;
end
lcm = a*b/m;
fprintf('lcm is %d.', lcm);

You can also remove fprintf('lcm is %d.', lcm); and change " lcm = a*b/m; " to " lcm = a*b/m " to print the value of lcm in command window.