How to fix this loop?

C = {1,2,3,1,4,6};

%for i = 1:length(C)
   List = cell(size(C)); %creating empty list
   for i = 1:length(C)
       if isequal(C{i}, 1)
           List(1) = C(i);
       else
           List(2) = C(i);
       end
   end

I GET A OUTPUT OF LIST AS =

BUT MY OUTPUT SHOULD LOOK LIKE:

IN cell 1 = [1,1]

IN CELL 2 = [2,3,4,6]

THE PROBLEM IS IT STORES THE LAST ELEMENT ENCOUNTERED , BUT IT SHOULD STORE ALL ELEMENTS ENCOUNTERED. HOW TO FIX THIS??

Answer 1

[Stephen23]

Simpler with a numeric vector:

>> V = [1,2,3,1,4,6];
>> List = {V(V==1),V(V~=1)};
>> List{1}
ans =
   1   1
>> List{2}
ans =
   2   3   4   6

Note: to get V from the cell array C:

V = [C{:}];

But if you really want to write inefficient code using a loop:

List = cell(1,2);
for k = 1:numel(C)
    if isequal(C{k}, 1)
        List{1} = [List{1},C{k}];
    else
        List{2} = [List{2},C{k}];
    end
end

which produces exactly the same output less efficiently using more lines of code.

[Stephen23]

Try this:

C = {1,2,3,1,4,6};
List = cell(1,2);
for k = 1:numel(C)
    if isequal(C{k}, 1)
        List{1} = [List{1},C{k}];
    else
        List{2} = [List{2},C{k}];
    end
end

giving

>> List{1}
ans =
     1   1
>> List{2}
ans =
     2   3   4   6