Want to get all outputs together as one in image processing

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Shahrin Islam
Shahrin Islam el 27 de Jul. de 2018
Editada: Guillaume el 29 de Jul. de 2018
Hello. Here I am attaching a file. I am implementing different edge detection methods and would like to have my outputs as per the following format attached. I am a new learner. Please help me. Thanks in advance.
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KALYAN ACHARJYA
KALYAN ACHARJYA el 27 de Jul. de 2018
Editada: KALYAN ACHARJYA el 27 de Jul. de 2018
Have you checked the answers? I have provided the three ways- More detail here

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Respuestas (2)

KALYAN ACHARJYA
KALYAN ACHARJYA el 27 de Jul. de 2018
Editada: KALYAN ACHARJYA el 27 de Jul. de 2018
fileFolder=fullfile(matlabroot,'toolbox','images','imdata');
dirOutput=dir(fullfile(fileFolder,'AT3_1m4_*.tif'));
%Above line>>tif-image format, change it as per the image format
fileNames={dirOutput.name};
montage(fileNames, 'Size', [4 4]); %16 images 4 by 4 blocks, you can change it
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KALYAN ACHARJYA
KALYAN ACHARJYA el 27 de Jul. de 2018
You can reduce the space between subplot by using this custom function
Another way you can change the aspect ration visit here
Hope my Answers help you
Good Wishes
Shahrin Islam
Shahrin Islam el 28 de Jul. de 2018
Can you help me with following code. [ha, pos] = tight_subplot(3,2,[.01 .03],[.1 .01],[.01 .01]) for ii = 1:6; axes(ha(ii)); plot(randn(10,ii)); end set(ha(1:4),'XTickLabel',''); set(ha,'YTickLabel','')

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Guillaume
Guillaume el 27 de Jul. de 2018
img = imread('cameraman.tif');
figure;
subplot(2, 3, 1); imshow(img);
subplot(2, 3, 2); imshow(imbinarize(img));
subplot(2, 3, 3); imshow(edge(imbinarize(img), 'Sobel'));
subplot(2, 3, 4); imshow(edge(imbinarize(img), 'Prewitt'));
subplot(2, 3, 5); imshow(edge(imbinarize(img), 'Roberts'));
subplot(2, 3, 6); imshow(edge(imbinarize(img), 'log'));
  4 comentarios
Image Analyst
Image Analyst el 28 de Jul. de 2018
Do you need any other help with it?
Guillaume
Guillaume el 29 de Jul. de 2018
Editada: Guillaume el 29 de Jul. de 2018
"Can you help me with following code."
Looks fine as it is. In order to help we would first need to know what problem you have with it.
PS: I've formatted your post for you. Follow Image Analyst's link to learn how to do that as I won't keep doing it for you.

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