How to apply function on every pair of rows of a matrix?

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Soul Free
Soul Free el 29 de Jul. de 2018
Editada: Stephen23 el 1 de Ag. de 2018
Hi, I'm new to matlab and I need help. I'm supposed to make a m x n matrix called M and it's elements are -1, 1 and 0.
I need to write a function called d(x,y) which returns 1 if (x = -1) and (y = 1). And returns 0 otherwise.
and another function called h(m(i),m(k)) which calculates the sum of d(m(i,j),m(k,j)) in every column and it is defined to find the distance between row i and row k:
For example Suppose M = [-1 0 -1; 1 -1 -1; 0 1 1].
If I calculate h for the 1st row and 2nd row(i = 1 and k = 2) it's Sum of d(m(1,j),m(2,j) for j from 1 to 3 which is d(m11,m21) + d(m12,m22) + d(m13,m23) = d(-1,1) + d(0,-1) + d(-1,-1) = 0+ 0 + 0 =0 .
Then I need h for every pair of rows. I'm confused. I tried writing d function as follows:
function d = d( x, y )
if (x==1) & (y==-1)
d = 1;
else
d = 0;
end
end
Then I tried to find h for row 1 and row 2 of the example matrix:
M = [-1 0 -1; 1 -1 -1; 0 1 1];
m=size(M,1);
n=size(M,2);
for i=1:2
h = sum(d(M(i,1:n)));
end
h returns 0 and works fine. I need to repeat this for every pair of matrix rows. For example for M which has 3 rows there will be 3 pairs of rows (3 choose 2) and h must be 1 x 3 (one sum for every pair).

Respuestas (1)

Stephen23
Stephen23 el 30 de Jul. de 2018
Editada: Stephen23 el 30 de Jul. de 2018
Perhaps something like this:
d = @(x,y)+(x==1&y==-1);
sum(bsxfun(d,permute(M,[1,3,2]),permute(M,[3,2,1])),3)
And tested:
>> M = [-1 0 -1; 1 -1 -1; 0 1 1]
M =
-1 0 -1
1 -1 -1
0 1 1
>> d = @(x,y)+(x==1&y==-1);
>> sum(bsxfun(d,permute(M,[1,3,2]),permute(M,[3,2,1])),3)
ans =
0 0 0
1 0 1
0 1 1
  5 comentarios
Stephen23
Stephen23 el 31 de Jul. de 2018
Editada: Stephen23 el 1 de Ag. de 2018
@Soul Free: the screenshot in your question
shows that the row indices i and k are not specified or summed over. As far as I can tell, this means you will have all combinations of rows i=1:m and k=1:m, thus giving an mxm matrix. If this is not the correct interpretation, please explain in more detail. It would also help if you provided the expected output for your example matrix M.
Soul Free
Soul Free el 31 de Jul. de 2018
Editada: Soul Free el 31 de Jul. de 2018
Thanks for your answer. I think i and k are constants every time we calculate h and I want h for j=1:n (j shows the column index of matrix, i and k are rows and are from 1 to m not n) for every pair of rows.(for all combinations of i=1:m and k=1:m) This explains more:
HD is supposed to return the distance of row i and row k. so for example if my matrix has 3 rows I'll have 3 pair of rows (3 choose 2) and HD must be 1 x 3. One HD for every pair of i=1:n and k=1:n where i ~=k.

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