excuse could someone correct or modify this routine

X(1)=1;
For i=1:100
Disp(x)
X(i+1)=sin(x(i))
End

[jose guevara]

Quisiera que por favor alguien me ayudara la rutina da muchos valores solo quisiera saber si se puede modificar para que de solo los cien valores

Answer 1

[Walter Roberson]

X(1)=1;
for i=1:100
  disp(x(i))
  X(i+1)=sin(x(i));
end

Answer 2

[jose guevara]

friend excuse my question is if you can modify the algorithm to prevent me from that amount of values and only the hundred that I ask could you please help me

[Dennis]

X(1)=1;
for i=1:100
   X(i+1)=sin(x(i));
end
disp(x(100))

[Walter Roberson]

Note: the 100'th output is x(100), the way Dennis shows. But you also compute the 101'st output, which will be at x(101)

[Dennis]

I was thinking exactly the same and even edited it. Then i realised that we display x and not X.

[Walter Roberson]

Oh, good point. So it would be

X(1)=1;
for i=1:100
   X(i+1)=sin(x(i));
end

disp(X(100))

or

disp(X(101))