could anyone help me how to reduce the circshift to half of it.

By using circshift i am getting 12 times what can be done inorder to reduce 12 to 6(which means half of it). Could anyone please help me on this.

[Domanic]

Hi Prabha,

Please could you give a code example for what you're trying to do? circshift does not reduce the length of a vector, it just changes the order of the elements of that vector.

[KSSV]

Read the documentation of circshift. If you enter 12 inputs, you will get 12 outputs only.

[Prabha Kumaresan]

yes i can understand circshift does not reduce the length.

this was the code which i am working on

A_master=1:12;
for k=1:numel(A_master)
    fprintf('\nPossibilities %02d:\n',k);
    A=circshift(A_master,1-k,2);
    B=0;
    while ~isempty(A)
        B=B+1;
        if B>numel(A)
            ind=1;
            B=1;%reset B
        else
            ind=[1 (numel(A)-B+2):numel(A) ];
        end
        C=A(ind)
        A(ind)=[];
end
end

If i run the code it executes and gives me the result.But I dont want to have all the possibilities. Instead I want to get the possibilities 1,3,5,7,9,11. Could you help me on this.

[Stephen23]

@Prabha Kumaresan: this is clearly related to your earlier questions of the last two days. Rather than showing us broken code with no comments or help or explanation, it would actually make things a lots easier if you explained what you are trying to achieve. Forget about your code attempts, they don't help us and are possibly not a very good solution anyway. Show us a simple example, complete with input and output arrays, so that we can understand what you want to achieve.

http://xyproblem.info/

https://meta.stackexchange.com/questions/66377/what-is-the-xy-problem

Answer 1

[Rik]

Just change the for-loop header:

A_master=1:12;
for k=1:2:numel(A_master)%[1 3 5 7 9 11] for 12, [1 3 5] for 6, etc
    fprintf('\nPossibilities %02d:\n',k);
    A=circshift(A_master,1-k,2);
    B=0;
    while ~isempty(A)
        B=B+1;
        if B>numel(A)
            ind=1;
            B=1;%reset B
        else
            ind=[1 (numel(A)-B+2):numel(A) ];
        end
        C=A(ind)
        A(ind)=[];
end
end

[Prabha Kumaresan]

thanks.It works