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How to extract a specific value from a loop.

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Westin Messer
Westin Messer el 31 de Ag. de 2018
Comentada: Dennis el 3 de Sept. de 2018
Hello
I wrote this code to model a simple projectile motion problem. What I would like to do now is output the value for x after 2 seconds but I don't know how to pull just one value out of a for loop.
%Projectile motion
v0= 10;
a= 45;
h= .04;
a=a*pi/180;
g=9.8; %acceleration due to gravity in m/s^2
xmax=v0^2*sin(2*a)/g;
ymax=v0^2*sin(a)^2/(2*g);
td=2*v0*sin(a)/g; %total time
x1=0;
y1=0;
figure('color','white');
for t=0:h:td+h
plot(x1,y1,'bo')
hold all
xlim([0 1.1*xmax]);
ylim([0 1.1*ymax]);
title('Projectile Motion');
xlabel('Distance in meter');
ylabel('Height in meter');
getframe;
x1=x1+h*v0*cos(a); %Euler's method for x
y1=y1+h*(v0*sin(a)-g*t);%Euler's method for y
% x1(2) % this is where I'm having the problem
end

Respuesta aceptada

M
M el 31 de Ag. de 2018
t is your time variable, so you have to use it to test if it's equal to 2seconds.
if t==2 % assumes your time units is seconds
x_2sec=x1;
end
but in your code, t will never reach 2 seconds.
  4 comentarios
M
M el 3 de Sept. de 2018
When I do that nothing outputs. Matlab doesn't seem to recognize that if statement. Am I using it wrong?
Your time step is equal to 0.4, so your time variable will be succesively equal to t=1.28 and 1.32, and your condition will never be satisfied.
Dennis
Dennis el 3 de Sept. de 2018
To check if t==1.32 would not work either. Due to floating point limitations t will not be exactly 1.32.

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GK
GK el 31 de Ag. de 2018
Yes you can. 1. If you remove semicolon at the end of expression, MATLAB simply shows it at the command line 2. Alternately, you can also print it in excel file using- xlswrite('x1values.xlsx', x1);

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