how can i apply 1 of k coding scheme on 2D MATRIX

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GHUFRAN AHMAD KHAN
GHUFRAN AHMAD KHAN el 12 de Sept. de 2018
Comentada: GHUFRAN AHMAD KHAN el 12 de Sept. de 2018
the order of matrix can be any number except 1.
  3 comentarios
GHUFRAN AHMAD KHAN
GHUFRAN AHMAD KHAN el 12 de Sept. de 2018
Editada: GHUFRAN AHMAD KHAN el 12 de Sept. de 2018
the sum of each row should be 1 and each entry should be 0 or 1 is called 1 of k coding scheme and below are one question solution.
>> C = [1,1,2,3,1,3,2];
>> R = 1:numel(C);
>> A = zeros(numel(C),max(C));
>> A(sub2ind(size(A),R,C)) = 1
A = 1 0 0; 1 0 0; 0 1 0; 0 0 1; 1 0 0; 0 0 1; 0 1 0
Rik
Rik el 12 de Sept. de 2018
So you already have working code? Then what is your question?

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Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 12 de Sept. de 2018
C = randi([1,3],2,4)
[m,n] = size(C);
k = max(C(:));
out = zeros(n,k,m);
[ii,kk] = ndgrid(1:m,1:n);
out(sub2ind([n,k,m],kk(:),C(:),ii(:))) = 1
  5 comentarios
Andrei Bobrov
Andrei Bobrov el 12 de Sept. de 2018
use
C = A + 1;
[m,n] = size(C);
k = max(C(:));
out = zeros(n,k,m);
[ii,kk] = ndgrid(1:m,1:n);
out(sub2ind([n,k,m],kk(:),C(:),ii(:))) = 1;
GHUFRAN AHMAD KHAN
GHUFRAN AHMAD KHAN el 12 de Sept. de 2018
here this message is showing when i am seeing the value of the out variable.
_ Cannot display summaries of variables with more than 524288 elements._

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