What is f ? And how big is it?
How to fix index in a parfoor loop?
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Andreu Angles Castillo
el 13 de Sept. de 2018
Comentada: Andreu Angles Castillo
el 18 de Sept. de 2018
I have the following code and get indexing error
parfor dt=0:round(tmax/step)
fprintf(1,'\b\b\b\b\b%05.2f',dt);
for dm=0:dt
A(dm+1,dt+1) = f(dm,dt);
end
end
It does not make sense, for me, because each loop of the first for is stand alone in the variable dt. The size of A has been prefixed.
The error messages on the script are:
-The PARFOOR loop cannot run due to the way varaiable 'A' is used. (On line 1)
-Valid indices for 'A' are resticted in PARFOR loops. (On line 4)
Error when run:
Error: The variable A in a parfor cannot be classified. See Parallel for Loops in MATLAB, "Overview".
4 comentarios
Stephen23
el 13 de Sept. de 2018
@Andreu Angles Castillo: please give the complete error message. This means all of the red text.
Andreu Angles Castillo
el 14 de Sept. de 2018
Editada: Andreu Angles Castillo
el 14 de Sept. de 2018
Respuesta aceptada
Titus Edelhofer
el 14 de Sept. de 2018
Hi Andreu,
agreed, it looks as if this case could be handled. But it is fairly easy to work around this by separating the inner loop from the parfor loop:
n = round(tmax/step) + 1;
parfor dt=0:round(tmax/step)
fprintf(1,'\b\b\b\b\b%05.2f',dt);
col = zeros(n, 1);
for dm=0:dt
col(dm+1) = f(dm, dt);
end
A(:, dt+1) = col;
end
Titus
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