Changing letters to other letters with regexprep
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Ryoma Kawakami
el 28 de Sept. de 2018
Comentada: Walter Roberson
el 28 de Sept. de 2018
I'm trying to change letters in a string to different ones with one line of code. I simplified my code down to the following:
regexprep('ab',{'a','b'},{'b','c'});
Ideally, this would output 'bc'. Currently, regexprep runs through the string twice and ends up outputting 'cc'.
Is there any way to prevent this from happening? Is it possible with regexprep? Also, I would prefer to keep the letters as strings, as I'm planning on using the 'preservecase' condition.
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Stephen23
el 28 de Sept. de 2018
Editada: Stephen23
el 28 de Sept. de 2018
>> str = 'a':'z'
str = abcdefghijklmnopqrstuvwxyz
>> old = 'bcd';
>> new = 'abc';
>> [X,Y] = ismember(str,old);
>> str(X) = new(Y(X))
str = aabcefghijklmnopqrstuvwxyz
Note that this works efficiently for any characters, not just a limited subset. In order to use regexprep you would probably need to use a dynamic replacement expression.
1 comentario
Walter Roberson
el 28 de Sept. de 2018
Well, any characters representable in the first 65536 code points ;-) If you have codepoints beyond that, such as Linear B or CJK Unified Ideograms like ? then you would need more work.
Más respuestas (2)
OCDER
el 28 de Sept. de 2018
Note that regexprep will replace things Sequentially.
regexprep('ab',{'a','b'},{'b','c'});
ab -> bb -> cc
To fix, reverse order like this:
regexprep('ab',{'b', 'a'},{'c', 'b'});
ab -> ac -> bc
Walter Roberson
el 28 de Sept. de 2018
old = 'bcd';
new = 'abc';
lookup = char(0:255);
lookup(old+1) = new;
str = 'a':'z'
str = lookup(str+1)
You do not need to add 1 if you are willing to omit the possibility of char(0) being in the string.
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