Borrar filtros
Borrar filtros

How to replace matrix value with string from cell array?

1 visualización (últimos 30 días)
Johnny Birch
Johnny Birch el 1 de Oct. de 2018
Comentada: Johnny Birch el 2 de Oct. de 2018

I have a cell array of string and a data matrix. How do I replace the value in the data matrix with the strings marked by ‘#’. I want the output to be a cell array of strings like the “output” in the script below.

cell = {
    '# 2.537'    '1.219'      '0.457'    '0.214'    '# 0.120'    '0.245'
    '3.244'      '# 1.400'    '0.649'    '0.515'    '0.207'      '0.075'
    '2.993'      '1.282'      '0.605'    '0.309'    '0.140'      '0.140'
    '3.278'      '1.507'      '0.885'    '0.405'    '0.160'      '0.111'
    '3.691'      '1.474'      '0.650'    '0.316'    '0.180'      '0.155'}
data=[
    0.8147    0.0975    0.1576    0.1419    0.6557    0.7577
    0.9058    0.2785    0.9706    0.4218    0.0357    0.7431
    0.1270    0.5469    0.9572    0.9157    0.8491    0.3922
    0.9134    0.9575    0.4854    0.7922    0.9340    0.6555
    0.6324    0.9649    0.8003    0.9595    0.6787    0.1712]
output={
    '# 2.537'   '0.0975'    '0.1576'    '0.1419'    '# 0.120'   '0.7577'
    '0.9058'    '# 1.400'   '0.9706'    '0.4218'    '0.0357'    '0.7431'
    '0.1270'    '0.5469'    '0.9572'    '0.9157'    '0.8491'    '0.3922'
    '0.9134'    '0.9575'    '0.4854'    '0.7922'    '0.9340'    '0.6555'
    '0.6324'    '0.9649'    '0.8003'    '0.9595'    '0.6787'    '0.1712'}

Respuesta aceptada

Jan
Jan el 2 de Oct. de 2018
output = sprintfc('%.4f', data);
index = strncmp(c, '#', 1);
output(index) = c(index);

Más respuestas (1)

jonas
jonas el 1 de Oct. de 2018
Editada: jonas el 1 de Oct. de 2018
Cell is a built in function so avoid using it as a variable name. Anyway, you can try this:
mask=logical(count(cell,'#'))
data=cellstr(string(a))
data(mask)=cell(mask)
data =
5×6 cell array
{'# 2.537'} {'0.0975' } {'0.1576'} {'0.1419'} {'# 0.120'} {'0.7577'}
{'0.9058' } {'# 1.400'} {'0.9706'} {'0.4218'} {'0.0357' } {'0.7431'}
{'0.127' } {'0.5469' } {'0.9572'} {'0.9157'} {'0.8491' } {'0.3922'}
{'0.9134' } {'0.9575' } {'0.4854'} {'0.7922'} {'0.934' } {'0.6555'}
{'0.6324' } {'0.9649' } {'0.8003'} {'0.9595'} {'0.6787' } {'0.1712'}
  1 comentario
Johnny Birch
Johnny Birch el 1 de Oct. de 2018
Editada: Johnny Birch el 1 de Oct. de 2018
Hi Jonas, thanks a lot for your answer. I changed the "cell" to "c", but I get this error:
Undefined function 'count' for input arguments of type 'cell'.
mask=logical(count(c,'#'))

Iniciar sesión para comentar.

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2015b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by