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Calculate distance between a point and a contour line

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Tumelo Maja
Tumelo Maja el 16 de Oct. de 2018
Editada: jonas el 16 de Oct. de 2018
I want to calculate distance between points of the trajectory(grey line) and the 1000m contour (dash black line) as shown on the attached image. I want the distance to be in km/m
Thanks for the help in advance
  3 comentarios
Tumelo Maja
Tumelo Maja el 16 de Oct. de 2018
Editada: Tumelo Maja el 16 de Oct. de 2018
I have attached the trajectory vectors of the glider paths (greyline) and the contour matrix, and lon/lat vectors for the contour values
jonas
jonas el 16 de Oct. de 2018
Perfect, I will take a look!

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jonas
jonas el 16 de Oct. de 2018
Editada: jonas el 16 de Oct. de 2018
Here is my code so far. The units of the output is not entirely correct, but should be quite easy to fix.
% Trajectory
lat = lat_track;
lon = lon_track;
% Contour matrix for Z = 1000
C = contour(lon_cont,lat_cont,cont_vals,'levellist',-1000);hold on
close all;
% Remove some unnecessary data and save contour coordinates
[~,idx] = find(C(1,:)==-1000);
poly = [C(1,idx(1)+1:idx(2)-1);C(2,idx(1)+1:idx(2)-1)]'
C(:,C(1,:)==-1000) = [];
Clat = C(2,:)';
Clon = C(1,:)';
% Calculate closest distance between trajectory and contour
[K,d] = dsearchn([Clon,Clat],[lon,lat]);
% Check if the pts are inside or outside of the contour
in = inpolygon(lon,lat,poly(:,1),poly(:,2));
% Change sign of those inside
d(in) = -d(in);
% Plot contour
plot(Clon,Clat,'k.');hold on
% plot trajectory
scatter3(lon,lat,d,[],d)
% plot closest points
plot(Clon(K),Clat(K),'r.')
% Calculate arclength
[arclen,az] = distance(lon,lat,Clon(K),Clat(K),'rad')
The minimum distance in each point is stored in d and the index on the corresponding index in the contour matrix is stored in K. This means that the distance d(1) is the distance between [lon(1);lat(1)] and [Clon(K);Clat(K)]. The distance is currently in a weird unit of latitudes and longitudes, but you could calculate the actual distance by the distance function.
  6 comentarios
Tumelo Maja
Tumelo Maja el 16 de Oct. de 2018
Editada: Tumelo Maja el 16 de Oct. de 2018
Thank you very much. The solution works perfectly :-)
jonas
jonas el 16 de Oct. de 2018
My pleasure. Interesting question!

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