How do I rename a variable, as it changes in a Loop

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fadams18
fadams18 el 19 de Oct. de 2018
Editada: Stephen23 el 19 de Oct. de 2018
I have .mat file. and first I load my variables (Data_1,Data_2....Data_60) using
for i=1:60
load(['matfiles/Data_',num2str(i),'.mat']);
end
I want to use a loop to write to a spreadsheet instead of writing this 60 times. so I do this
for i=1:60
xlwrite('saved_file.xls',Data_1, sheetName,'B3') // Data_1 is one of the variable loaded above.Needs to change to Data_2 and so on.
end
now the question is I want to dynamically change the name in Data_1 every iteration using the loaded files. How can I do this.
  1 comentario
Stephen23
Stephen23 el 19 de Oct. de 2018
"I want to dynamically change the name in Data_1 every iteration using the loaded files. How can I do this."
Do NOT do this! Magically accessing/defining variable names is one way that beginners force themselves into writing slow, complex, buggy code. Read this to know why:
A much simpler and more efficient solution is to load the data into an output variable (which you should always be doing anyway, and then use struct2cell. Then your task is easy.

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Stephen23
Stephen23 el 19 de Oct. de 2018
Editada: Stephen23 el 19 de Oct. de 2018
This is easy, as long as there is only one variable loaded from each .mat file:
for k = 1:60
F = sprintf('Data%d.mat',k);
P = fullfile('matfiles',F);
S = load(F);
C = struct2cell(S);
N = sprintf('sheet%d',k);
xlswrite('saved_file.xls',C{1},N)
end
  3 comentarios
Stephen23
Stephen23 el 19 de Oct. de 2018
Editada: Stephen23 el 19 de Oct. de 2018
"is there a way to make the row update as well?"
Of course, just use sprintf to specify the address:
pos = sprintf('B%d',1+k);
xlwrite('saved_file.xls',C{1},sheetname,pos)
fadams18
fadams18 el 19 de Oct. de 2018

Thank man! remind me to buy u chocolate xD

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madhan ravi
madhan ravi el 19 de Oct. de 2018

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