solve a partial differential equation

Hi! I want to solve a second partial differential equation.
The general solution is
Which command should I use to get the general solution? I think dsolve doesn't work well. Thanks for helping me.

 Respuesta aceptada

Stephan
Stephan el 21 de Oct. de 2018
Hi,
the following code solves the equation with the initial conditions:
y(0)=0
dy/dx(0)=0
Then it rewrites the result in terms of sin ans cos:
syms y(x) x E I N P c l Dyt(x)
eqn = E*I*diff(y,x,2)+N*y == -P*c/l*x;
[eqns, vars] = reduceDifferentialOrder(eqn,y);
conds = [y(0)==0,Dyt(0)==0];
sol = dsolve(eqns,conds);
sol_sin = simplify(rewrite(sol.y,'sin'))
I think that was the question.
Best regards
Stephan

10 comentarios

Yuchi Kang
Yuchi Kang el 21 de Oct. de 2018
Thanks for helping me. But it seems wrong.
In addition, reduceDifferentialOrder is used here. Could you please tell me a little bit about the reason?
Best regards
Yuchi Kang
Stephan
Stephan el 21 de Oct. de 2018
For me the code runs fine. Is there a copy paste mistake? Which Release do you use?
Yuchi Kang
Yuchi Kang el 21 de Oct. de 2018
Thanks for your reply. I have checked carefully, there is no paste mistake. R2017a is used.
madhan ravi
madhan ravi el 21 de Oct. de 2018
Works for me
Stephan
Stephan el 21 de Oct. de 2018
Editada: Stephan el 21 de Oct. de 2018
Im using R2018b - let me check this. Maybe there is a difference in dsolve.
Can you show us the result of typing this in commmand line:
eqns
vars
after executing the code ans getting the error?
Here is the photo for executing the two commands.
I try to use R2018a. It does work and here is the result
sol_sin =
(N^(1/2)*P*c*x*sin((x*((-E*I*N)^(1/2)*1i + E^(1/2)*I^(1/2)*N^(1/2)))/(E*I))*1i - E^(1/2)*I^(1/2)*P*c*cos((N^(1/2)*x)/(E^(1/2)*I^(1/2)))*1i + E^(1/2)*I^(1/2)*P*c*cos((x*((-E*I*N)^(1/2)*1i + E^(1/2)*I^(1/2)*N^(1/2)))/(E*I))*1i)/(N^(3/2)*l)
Stephan
Stephan el 21 de Oct. de 2018
Nice. Problem solved?
Yuchi Kang
Yuchi Kang el 21 de Oct. de 2018
Yes. Almost done. Thanks. But I have a minor problem with the results. If I want to use this equation k^2=N/E/I to simplify my results. May I use the subs command?
Best regards Yuchi Kang
Stephan
Stephan el 21 de Oct. de 2018
Editada: Stephan el 21 de Oct. de 2018
yes - this is what subs is for - i would suggest to this before reducing the differential order:
syms y(x) x E I N P c l Dyt(x) k
eqn = diff(y,x,2)+N/E*I*y == -P*c/(l*E*I)*x;
eqn = subs(eqn,(N/E*I),k^2)
[eqns, vars] = reduceDifferentialOrder(eqn,y);
conds = [y(0)==0,Dyt(0)==0];
sol = dsolve(eqns,conds)
sol_sin = rewrite(sol.y,'sin')
which gives:
sol_sin =
- ((P*c*1i)/(2*E*I*k^3*l) + (P*c*(- 1 + k*x*1i)*(sin(k*x)*1i - 2*sin((k*x)/2)^2 + 1)*1i)/(2*E*I*k^3*l))*(sin(k*x)*1i + 2*sin((k*x)/2)^2 - 1) - ((P*c*1i)/(2*E*I*k^3*l) + (P*c*(1 + k*x*1i)*(sin(k*x)*1i + 2*sin((k*x)/2)^2 - 1)*1i)/(2*E*I*k^3*l))*(sin(k*x)*1i - 2*sin((k*x)/2)^2 + 1)
You can also get rid of the imaginary parts of the results by making some assumptions. For example i suspect E to be youngs modul, which should be a real number and positive always:
syms y(x) x E I N P c l Dyt(x) k
eqn = diff(y,x,2)+N/E*I*y == -P*c/(l*E*I)*x;
eqn = subs(eqn,(N/E*I),k^2)
[eqns, vars] = reduceDifferentialOrder(eqn,y);
conds = [y(0)==0,Dyt(0)==0];
assume([x P c l k],'real');
assumeAlso(c>=0 & l>=0 & k>=0);
assumptions
sol = dsolve(eqns,conds)
sol_sin = rewrite(sol.y,'sin')
results in:
sol_sin =
(P*c*sin(k*x))/(E*I*k^3*l) - (P*c*x)/(E*I*k^2*l)
You should check if the assumptions i made are correct in your case and modify them if needed.
Stephan
Stephan el 21 de Oct. de 2018
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el 20 de Oct. de 2018

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el 21 de Oct. de 2018

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