Code for equation with ln

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Sayeed
Sayeed el 21 de Oct. de 2018
Comentada: Star Strider el 21 de Oct. de 2018

How can i Code it?

u=0.23 y=0.3 v=0.00001

u/u’=5*log(u’*y/v)-3.05

u’=?

I need to find the value of u’.

Respuestas (1)

Star Strider
Star Strider el 21 de Oct. de 2018
Try this:
u=0.23;
y=0.3;
v=0.00001;
fcn = @(ustar,u,y,nu) 5*log(ustar.*y/nu)- 3.05 - u/ustar;
ustar = fsolve(@(ustar)fcn(ustar,u,y,v), 1)
ustar =
0.00918407730971717
  2 comentarios
Sayeed
Sayeed el 21 de Oct. de 2018
It is somehow not working to my matlab. Can you please send me the code file with attachment?
Star Strider
Star Strider el 21 de Oct. de 2018
I already posted all the code that is needed to solve this problem.
You need to have the Optimization Toolbox installed to use fsolve.
You will have fminsearch regardless, so try using fminsearch on the norm of ‘fcn’:
ustar = fminsearch(@(ustar)norm(fcn(ustar,u,y,v)), 1)
ustar =
0.00918426513671787

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