Finding the index of a matrix corresponding to a particular column of another matrix

I have two matrices like, A= [4 12 ; 2 6] and B = [9 4 8 12 ; 2 2 4 6] I want get the relevant index of B corresponding to the 1st column in matrix A. (i.e- first column of A is 4 and 2. And the index corresponding to that in matrix A is index 2 )

[madhan ravi]

Give an example of your desired result

[Eranja Noopehewa]

first column of A is 4 and 2. And the index corresponding to that column in matrix A is index 2

Answer 1

[Rik]

You can try this:

A= [4 12 ; 2 6];
B = [9 4 8 12 ; 2 2 4 6];
selected_col=1;
col_in_B=find(all(A(:,selected_col)==B,1));

[madhan ravi]

+1 @Rik didn’t get command all instead i used any , thank you :)

Answer 2

[madhan ravi]

A= [4 12 ; 2 6] 
B = [9 4 8 12 ; 2 2 4 6] 

idx=find(any(A(:,1)==B))

[Eranja Noopehewa]

This gives my answer as idx= 1 2

[madhan ravi]

If it’s not what you expect then you should explain more on what you want to achieve

[Eranja Noopehewa]

I need to get it as idx = 2

[madhan ravi]

See Rik’s answer

Answer 3

[Matt J]

 [~,idx]=ismember(A(:,1).',B.','rows')