Is there any way to convert "*" to ".*"?
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Fernando Pérez Lara
el 4 de Nov. de 2018
Comentada: John D'Errico
el 4 de Nov. de 2018
Is there any way to convert this "*" into this ".*"
My output is this
- 1.8420821237718587592979702094453*x^3 + 3.2914765235937450960079786455026*x^2 - 0.44362298592685589504469589883229*x + 0.023160255314885146854519959447316
Thanks!
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Respuesta aceptada
John D'Errico
el 4 de Nov. de 2018
Editada: John D'Errico
el 4 de Nov. de 2018
Why do you think you need to do so?
In the symbolic expression you refer to, all of the * operators are multiplying a scalar numeric constant times x to some power. This is automatically done by the * operator.
It would have been arguably more important to convert those ^ to .^ operators, since ^ does not trivially do what you may be asking in vectorized form.
So, suppose I have the symbolic expression...
vpa(F)
ans =
- 1.8420821237718587592979702094453*x^3 + 3.2914765235937450960079786455026*x^2 - 0.44362298592685589504469589883229*x + 0.023160255314885146854519959447316
matlabFunction(F)
ans =
function_handle with value:
@(x)x.*(-4.436229859268559e-1)+x.^2.*3.291476523593745-x.^3.*1.842082123771859+2.316025531488515e-2
As you can see, matlabFunction did what you wanted, I think. So you CAN do what you wanted.
3 comentarios
John D'Errico
el 4 de Nov. de 2018
It is a feature that I seem to forget too often myself. But then there are many capabilities of MATLAB that are easy to miss, especially in any language that continuously (slowly) changes with time, adding new features as we go.
Más respuestas (2)
Walter Roberson
el 4 de Nov. de 2018
If you have a character vector holding the expression then you can use vectorize()
(matlabFunction calls vectorize)
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