# How can I draw these rectangles in a loop using psychtoolbox... there must be a better way than what I've done. Thanks for your help!!

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Olivia Krieger el 8 de Nov. de 2018
Comentada: Olivia Krieger el 8 de Nov. de 2018
% Draw base rectangle
r1=[0 0 20 20];
r2=OffsetRect(r1, 200,200);
r3=OffsetRect(r1, 200,235);
r4=OffsetRect(r1, 235,200);
r5=OffsetRect(r1, 235,235);
r6=OffsetRect(r1, 300,235);
r7=OffsetRect(r1, 300,200);
r8=OffsetRect(r1, 335,200);
r9=OffsetRect(r1, 335,235);
r10=OffsetRect(r1, 200,100);
r11=OffsetRect(r1, 200,135);
r12=OffsetRect(r1, 235,100);
r13=OffsetRect(r1, 235,135);
r14=OffsetRect(r1, 300,100);
r15=OffsetRect(r1, 300,135);
r16=OffsetRect(r1, 335,100);
r17=OffsetRect(r1, 335,135);
Screen('FillRect',win, [0, 0, 1], r2);
Screen('FillRect',win, [0, 0, 1], r3);
Screen('FillRect',win, [0, 0, 1], r4);
Screen('FillRect',win, [0, 0, 1], r5);
Screen('FillRect',win, [0, 0, 1], r6);
Screen('FillRect',win, [0, 0, 1], r7);
Screen('FillRect',win, [0, 0, 1], r8);
Screen('FillRect',win, [0, 0, 1], r9);
Screen('FillRect',win, [0, 0, 1], r10);
Screen('FillRect',win, [0, 0, 1], r11);
Screen('FillRect',win, [0, 0, 1], r12);
Screen('FillRect',win, [0, 0, 1], r13);
Screen('FillRect',win, [0, 0, 1], r14);
Screen('FillRect',win, [0, 0, 1], r15);
Screen('FillRect',win, [0, 0, 1], r16);
Screen('FillRect',win, [0, 0, 1], r17);
% Show it on the display:
Screen('Flip', win);
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Jeff Miller el 8 de Nov. de 2018
One simple improvement is to make r a cell array. Add a command at the top like
r=cell(17,1);
r2=OffsetRect(r1, 200,200);
you would use
r{2}=OffsetRect(r{1}, 200,200);
Then, at the end, you could draw all the rectangles with 3 lines:
for i=2:17
Screen('FillRect',win, [0, 0, 1], r{i});
end
Screen('flip');
I'm sure you could do even better by working out a pattern to compute the various values of r, 2-17, but I'm not sure that would be worth the effort.
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### Más respuestas (1)

Olivia Krieger el 8 de Nov. de 2018
Thank you for your help! I would also like to compute a pattern (the computation I'm not worried about, but figuring out how to implement it is where I'm a little stuck.) I will have 64 squares total (which will most often be in the same position), however some boxes will change position. So I think it will be worthwhile for me to implement a pattern (at least for the main pattern).
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Jeff Miller el 8 de Nov. de 2018
There would be be many different ways to do this, and it is tough to say which one will be most convenient without studying your full pattern in detail. But you will probably want to use some kind of loop like this:
for i=2:17
newx = ???; % compute values here depending on your pattern.
newy = ???; % You will need 'if' statements if the values depend on i.
r{i}=OffsetRect(r1, newx,newy);
end
Olivia Krieger el 8 de Nov. de 2018
Thank you! I will try this

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