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How can I get the input arguments of a function and save them into an array ?

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Hi everyone,
I'd like to know how to get the input arguments of a function and put them into an array to be able to do a loop. I'm also looking of len(["file1.csv","file2.csv","file3.csv"]) =3 in matlab. Currently, I'm getting this : length(['file1.csv','file2.csv','file3.csv']) =27 and as I want to pass this array to a function to read the 3 files one after an other with a loop. Could you help me please ?
I thank you in advance for all your answers.
  2 Comments
Stephen23
Stephen23 on 12 Nov 2018
Edited: Stephen23 on 12 Nov 2018
@Bo Sarah: these are NOT the same:
["file1.csv","file2.csv","file3.csv"] % 1x3 string array
['file1.csv','file2.csv','file3.csv'] % 1x27 character vector
Do NOT confuse character arrays with string arrays. They have very different properties:

Answers (1)

Ashutosh Prasad
Ashutosh Prasad on 12 Nov 2018
You can define your function with a variable length argument list using varargin and then use the index of the cell array to refer to each of your input arguments. Given below is a sample function definition.
function var_arg(varargin)
if nargin == 3
disp(varargin(1));
disp(varargin(2));
disp(varargin(3));
end
end
length(["file1.csv","file2.csv","file3.csv"]) gives an output 3.
  1 Comment
Stephen23
Stephen23 on 12 Nov 2018
"length(["file1.csv","file2.csv","file3.csv"]) gives an output 3."
Sure, but that string array is not the same as the character vector in the original question.

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