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How to solve INDEX OUT OF BOUNDS ERROR? Please help me. Stuck in this for the past 10 days.

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eltn=30;
%%(b)Element Connectivity Table
count = 0 ;
conn = zeros([],3) ;
for i=1:30
for j=1:27
count = count+1 ;
conn(count,:) =[j,j+1,j+2]
end
end
%Here the Code for Assembling (OR) Global Mass Matrix
%x(i,j)=Kte_matrix(i,j); %DOUBT +=
for i=1:27
for j=1:27
MG_matrix(conn(eltn,i) - 1,conn(eltn,j) - 1)= Mte_matrix(i,j); (ERROR HERE)
end
end
How to convert conn matrix in this range??
Attempted to access conn(30,4); index out of bounds because size(conn)=[810,3].
Error in practisee2 (line 558) MG_matrix(conn(eltn,i) - 1,conn(eltn,j) - 1)= Mte_matrix(i,j);
  11 comentarios
Walter Roberson
Walter Roberson el 12 de Nov. de 2018
That is quite different initialisation than what you had before.
Virajan Verma
Virajan Verma el 13 de Nov. de 2018
That conn matrix is showing index out of bounds error as it has only 3 columns and for i>3, it has no elements to show. That is why i changed the initialization.

Respuestas (1)

KSSV
KSSV el 12 de Nov. de 2018
Check the function assemble in the link. This will help you.
  8 comentarios
Virajan Verma
Virajan Verma el 13 de Nov. de 2018
The value of conn(eltn,j) for j=1 should be 59. How can it be zero??
Stephen23
Stephen23 el 13 de Nov. de 2018
Editada: Stephen23 el 13 de Nov. de 2018
"The value of conn(eltn,j) for j=1 should be 59. How can it be zero??"
Who said that j is equal to one when that error occurs? I don't see anything in your code that means that j equals one when that error occurs. Try looking at the value of j after the error has occured, and you might just learn something about your code.

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