Borrar filtros
Borrar filtros

How can I get an average of different matrices stored as separate .mat files?

2 visualizaciones (últimos 30 días)
I have 24 different matrices of dimension 68X68, stored in a folder. I need to create a new matrix that is an average of all those matrices. Using previous FAQ from this forum, I tried :
Num = 24
for i = 1:Num
files = dir(sprintf('ii_Sub*.mat',i))
for k = 1:length(files)
fprintf('Current file : %s\n', files(k).name)
a = load(files(k).name)
meanmatrix = mean(a,24)
end
end
This is creating a 1X1 struct only, while the mean command shows an error as well. How best can I go about it?
  3 comentarios
Stephen23
Stephen23 el 13 de Nov. de 2018
@Native: please do not close threads that have already have answers.
Native
Native el 13 de Nov. de 2018
Editada: Native el 13 de Nov. de 2018
Sure, I was not aware of that. Closed it thinking that the purpose of the question was solved..
As for your earlier comment, thanks for pointing out the fallacies. I must admit that i have started to know the language of code only for a month now, so work in progress. Hope to learn a lot from this forum! :)

Iniciar sesión para comentar.

Respuesta aceptada

Stephen23
Stephen23 el 13 de Nov. de 2018
Editada: Stephen23 el 13 de Nov. de 2018
Assuming that each file contains exactly one variable (a matrix) and that all matrices are the same size and type:
S = dir('*.mat');
N = numel(S);
C = cell(1,N);
for k = 1:N
T = load(S(k).name)
C(k) = struct2cell(T);
end
M = cat(3,C{:})
mean(M,3)
  9 comentarios
Stephen23
Stephen23 el 20 de Jul. de 2021
@João Vítor Batista Pires Santos: you could try something like this:
for k = 1:N
C{k} = ncread(S(k).name,'PRMSL_L101'); % PRMSL_L101 = Pressure (17x17x4)
end
A = cat(4,C{:});
M = mean(A,4)

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by