Combinations of a vector with replacement
    3 visualizaciones (últimos 30 días)
  
       Mostrar comentarios más antiguos
    
    klb
 el 13 de Nov. de 2018
  
    
    
    
    
    Comentada: klb
 el 15 de Nov. de 2018
             Hello everyone.  A = [2 3 4].    I am trying to generate these 2 combinations: 
- 22, 23 ,24 ,32 ,33 ,34, 42 ,43 ,44 (order matters so 23 not equal to 32 so nchoosek(A,2) does not work)
 - 222, 233, 232, 234, 243, 333, 322, 323, 344, 343 , 324,342, 422, 424, 433 ,434 , 432, 423, 444. perms(A) does not do the job here because it is without replacement.
 
how can I do these?
0 comentarios
Respuesta aceptada
  Bruno Luong
      
      
 el 13 de Nov. de 2018
        
      Editada: Bruno Luong
      
      
 el 13 de Nov. de 2018
  
      A = [2 3 4]
[A1,A2] = ndgrid(A);
arrayfun(@(k) polyval([A2(k),A1(k)],10), 1:numel(A1))
[A1,A2,A3] = ndgrid(A);
arrayfun(@(k) polyval([A3(k),A2(k),A1(k)],10), 1:numel(A1))
3 comentarios
  Bruno Luong
      
      
 el 15 de Nov. de 2018
				
      Editada: Bruno Luong
      
      
 el 15 de Nov. de 2018
  
			Keep telling you guys of putting more care on your question. 
If you want a space then put a space.[2 2 3] is not 223.
A = [2 3 4]
[A1,A2,A3] = ndgrid(A);
[A3(:),A2(:),A1(:)]
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!