How to define edges in hist3 function

Hi, so I have some 2D data and I would like to make a histogram, I've seen that I can do that with hist3 function, but I would like to define edges for the bins, not just divide the data range into n bins of the same size. So I've made this code:
dD=(0:0.01:0.25);
diam=[1 2 3 4 5 10 15 20 30 40 50];
z=hist3([krateri_br(:,3) krateri_br(:,4)],'Edges',[diam dD]');
But every time I get an error:
??? Error using ==> hist3 at 132 Bin edges must be specified with a cell array containing two numeric vectors.__
Now, I've tried different combinations of parenthesis for edges vector, but nothing seems to work. I have a feeling that I'm making some elementary mistake, but cannot find it, so if someone knows how to solve this, please help.
Thank you in advance!

5 comentarios

Luffy
Luffy el 7 de Jul. de 2012
help says that edges is a two-element cell array of numeric vectors with monotonically non-decreasing values,
In your code you wrote it as a vector, try {diam dD}'
Marin
Marin el 9 de Jul. de 2012
Oh, yes, that solves it. Thank you.
I wasn't sure about the difference between an array and vector. So if I understood it correctly an array is defined by {}, while a vector is defined by []. Is that the only difference?
Oleg Komarov
Oleg Komarov el 9 de Jul. de 2012
Editada: Oleg Komarov el 9 de Jul. de 2012
A cell array is accessed with {}.
The [] are the horizontal concatenation operator.
Marin
Marin el 9 de Jul. de 2012
Oh, ok, that makes things a bit clearer. Thank you!
Chris
Chris el 31 de En. de 2015
Thank you!

Iniciar sesión para comentar.

Respuestas (0)

Categorías

Más información sobre Data Distribution Plots en Centro de ayuda y File Exchange.

Preguntada:

el 7 de Jul. de 2012

Comentada:

el 31 de En. de 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by