What is wrong with this code? Need help.

Main code:
clear all
close all
clc
M = [1 0 0
0 1 0
0 0 1];
x0=[-0.5; 0.2; 0.5];
options = odeset('Mass',M,'RelTol',1e-12,'AbsTol',[1e-14 1e-14 1e-14], 'Vectorized','on');
global t x y z dt alpha
dt=0.01;
for alpha=0.8800:0.0005:1.6000
alpha
clear n
clear m
[t,x]=ode15s(@equations,0:dt:500,x0);
n=length(x(:,1));
m=floor(n/2);
y=diff(x(m,n,1))/dt; %% Error Message at this line: Index exceeds matrix dimensions
z=diff(y)/dt;
k=1;
clear aa
for i=m:n
t0=t(i); %Comp. local max. pts for m<t<n
option=optimset('display','off');
zer=fsolve(@differ,t0,option);
if interp1(t(m:n-2),z,zer)>0
aa(k)=interp1(t(m:n),x(m:n,1),zer);
k=k+1;
end
end
kmax=k-1;
h=plot(alpha.*ones(1,kmax),aa,'r.');
hold on
set(h,'MarkerSize',0.1);
end
Function equations.m:
function xdot=equations(t,x)
global alpha
a=0.0005; b=0.01; eps=0.01; beta=-1; R=0.3;
xdot(1) = (-x(2) + alpha*x(1)^2 + beta*x(1)^3)/eps;
xdot(2) = x(1) - x(3) - R*x(2);
xdot(3) = a - b*x(2);
xdot = xdot';
end
Function differ.m:
function f=differ(a)
global t x dt
s=diff(x(m:n,1))/dt;
f=interp1(t(m:n-1),s,aa);
end

3 comentarios

KSSV
KSSV el 13 de Dic. de 2018
YOu specify your error...so that people can try to help you with out running your code.
KSSV
KSSV el 13 de Dic. de 2018
YOur size of x is 5001*3.....but at that line you are trying to extract 50001 columns...you need to think on this line:
n=length(x(:,1));
Your x is a 50001 x 3 array. m is 25000. n is 50001. What is your expectation as to what
y=diff(x(m,n,1))/dt;
will do for you? Even if x had that many columns, x(scalar,scalar,1) would be a scalar and diff() of a scalar is going to be empty.

Respuestas (0)

La pregunta está cerrada.

Etiquetas

Preguntada:

el 13 de Dic. de 2018

Cerrada:

el 20 de Ag. de 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by