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Splitting column to different length columns in matrix

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Hüsamettin Taysi
Hüsamettin Taysi el 14 de Dic. de 2018
Editada: Omer Yasin Birey el 14 de Dic. de 2018
Hello, for example with the function below, I know that it is possbile split a column to same length columns. If we have 70 values, after this process we get 7x10 matrices.
a=reshape(a,10,[])
But my aim is for example, we have 30 values and I want to split them like;
  1. column 2.column 3.column
5 values 12 values 13 values
Is it possible?
Thanks in advance.

Respuestas (1)

Omer Yasin Birey
Omer Yasin Birey el 14 de Dic. de 2018
Editada: Omer Yasin Birey el 14 de Dic. de 2018
It is not possible in numerical array. However, you may do it with cell arrays by using mat2cell as Stephen mentioned in the comment section.
But it will look like this
C =
1 2
1) [1;2;3;4] [1;2;3;4;5]
Instead of this
  1. column 2.column 3.column
5 values 12 values 13 values
You can use array indexing if you don't mind zeros
a = zeros(13,3);
a(1:5,1) = randi(5,1);
a(1:12,2) = randi(5,1);
a(1:13,3) = randi(5,1);
And then maybe you can ignore the zeros somehow.
Or, better you can use cell arrays instead of double
a = cell(13,3);
a(1:5,1) = {1};
a(1:12,2) = {1};
a(1:13,3) = {1};
So you know there is no data stored in empty cells.

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