Copy file from one directory to another

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Marisabel Gonzalez
Marisabel Gonzalez el 17 de Dic. de 2018
Respondida: Prajwol Tamrakar el 27 de Mayo de 2020
Hi,
So I am using this piece of code to copy some files with similar names from several destination paths (e.g. file03431314, file6767464363, etc).
When I use 'file*' it assumes it is a directory, which is not...
When I actualy copy and paste the filename, e.g. 'file03431314', it works fine.
PS: the file that I want to copy does not have an extension.
How can I fix this?
Thanks
p1 = 'filepath'
% Copying file from respective path
pdest = 'mydestinationpath';
filename = 'file*';
source = fullfile(p1,filename);
destination = fullfile(pdest,filename);
copyfile(source,destination)
% Renaming
oldname = filename;
newname = '1_file.txt';
copyfile(oldname,newname);
% Deleting old file
delete(filename)
  1 comentario
Jan
Jan el 17 de Dic. de 2018
Editada: Jan el 17 de Dic. de 2018
What does this mean:
When I use 'file*' it assumes it is a directory, which is not...
What are the "it"s and why do you assume that it assumes that what is a directory?
Is renaming the files a part of the question?

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Respuestas (3)

Jan
Jan el 17 de Dic. de 2018
If there are really problems with the copy of a file pattern, do it explicitly with a loop:
psource = 'filepath'
pdest = 'mydestinationpath';
pattern = 'file*';
sourceDir = dir(fullfile(psource, pattern));
sourceDir([sourceDir.isdir]) = []; % Files only
for k = 1:numel(sourceDir)
sourceFile = fullfile(psource, sourceDir(k).name);
destFile = fullfile(pdest, sourceDir(k).name); % Or another name?
movefile(sourceFile, destFile);
end

Prajwol Tamrakar
Prajwol Tamrakar el 27 de Mayo de 2020
This issue of copying file to another directory is possibly due to "ready only access". Use 'f' option to override the read-only status of the destination folder.
copyfile(SourceFile, DestinyFile, 'f')

Omer Yasin Birey
Omer Yasin Birey el 17 de Dic. de 2018
Maybe you can get parts of the filename by using
[filepath,name,ext] = fileparts(file);
and after that you can use directly the name of the file instead of this "filename = 'file*';"
[filepath,name,ext] = fileparts(file);
filepath =
'H:\user4\matlab'
name =
'myfile'
ext =
'.txt'
once you get the name of the file by this, you can use it in your code.
  2 comentarios
Marisabel Gonzalez
Marisabel Gonzalez el 17 de Dic. de 2018
It's not just one file. I'm running simulations and I want to save the output files. All of them start with the same name but then are followed by a series of numbers. Also, the files don't have an extension. I save it as .txt but the original file doesn't have any extension.
Omer Yasin Birey
Omer Yasin Birey el 17 de Dic. de 2018
filename = 'file';
numbers = [1 2 3 4 5 1234324123 03431314 3431314123123 ..... ]
for i = 1:length(k)
nFile{i} = sprintf('%s_%d',filename,numbers(i));
end

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