im2col error in size
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Hi this is my code:
R=rand(162,72);
r=im2col(R,[2 2],'sliding');
R1=col2im(r,[2 2],size®,'sliding');
the size of R is [162 72];
when I use line 1 it is OK. It gives me a a matrix r with size of r=[4 11431]
but at line 2 to obtain R, when I want to convert them to the original matrix via col2im, it give me this error:
"To RESHAPE the number of elements must not change."
Can anybody help me please and tell me what is the problem?
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Image Analyst
el 16 de Jul. de 2012
What are you really trying to do? im2col() and col2im() are confusing functions that are probably going to be deprecated soon. How did you ever stumble upon those? Can't you do what you want to do with reshape() or blockproc() or something?
3 comentarios
Image Analyst
el 16 de Jul. de 2012
Editada: Image Analyst
el 16 de Jul. de 2012
I'm glad you explained that because now I can recommend nlfilter() as the proper way to do what you want to do. My advice is to not use reshape() but to use nlfilter(), or alternatively blockproc() if you don't have the Image Processing Toolbox.
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Sean de Wolski
el 16 de Jul. de 2012
Because you are using a 'sliding' block with im2col the number of elements in r is much bigger than the number in R. Compare:
numel(R)
numel(r)
What you have works with 'distinct' blocks as you would expect:
R=rand(162,72);
r=im2col(R,[2 2],'distinct');
R1=col2im(r,[2 2],size(R),'distinct');
5 comentarios
Image Analyst
el 17 de Jul. de 2012
That won't happen if you don't do that im2col/col2im stuff and use nlfilter instead.
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