Best way to split data into random partitions?

I am new to Matlab and still a student. For an assignment, I am stuck on this part.
Create 5 random partitions of the data, splitting each of the classes into 60% training and 40% testing.
I have two classes, Class One and Class Two.
How would I be able to do this?
classOne and classTwo is 10000x2 double histogram

 Respuesta aceptada

Cris LaPierre
Cris LaPierre el 12 de En. de 2019
Editada: Cris LaPierre el 12 de En. de 2019
I would use the dividerand function in the Deep Learning Toolbox.
For example
[trainInd,valInd,testInd] = dividerand(3000,0.6,0.2,0.2);
Just set the validation percentage to 0 if you don't need it.

5 comentarios

G. Nardi
G. Nardi el 12 de En. de 2019
Can you tell me what the values mean in your example? 30000, .6 (I am assuming is the training and), .2,.2)
Cris LaPierre
Cris LaPierre el 12 de En. de 2019
I assume you've looked at the documentation page, so I won't duplicate info from there.
This function returns indices. Indices can then be used to select data for training, validation or testing.
From what you mention, let's say ClassOne is 10000x2. I want 60% (6000 rows) for training and 40% (4000 rows) for testing. I'd do this
[trainInd,~,testInd] = dividerand(length(ClassOne),0.6,0,0.4);
Now when you need your training data, you would use
ClassOne(trainInd,:)
and when you need you testing data, you would use
ClassOne(testInd,:)
dividerand creates groups randomly, so you would get different groups each time you called it.
G. Nardi
G. Nardi el 12 de En. de 2019
i don't have that toolbox.
David Goodmanson
David Goodmanson el 12 de En. de 2019
HI Masaki,
Neither do I, but you can use somthing more basic like RandInd = randperm(n), which creates a vector containing a random arrangement of the numbers 1:n. Then you can take the first 60% (or whatever) of RandInd to be TrainInd, etc. and proceed from there.
G. Nardi
G. Nardi el 12 de En. de 2019
thanks! i appreciate it.

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