Creating a matrix which has particular order of element ?

Hello all,

I have to obtain a matrix. The matrix looks like

A=[1 0 0 0 0 0;0 2 0 0 0 0;3 0 4 0 0 0;0 5 0 6 0 0;7 0 8 0 9 0;0 10 0 11 0 12];

% There is a sequence.Odd row and even row. 
% ODD ROW- Element stasts from  first column 
% EVEN ROW- Element start from second coloumn
% Each element is +1 to the previous element.

I can do this with "FOR-LOOP". But is there some effiecient way to do this.

Thanks you !

Answer 1

[Andrei Bobrov]

m = 6;
n = 6;

lo = triu(~rem((1:n)' + (1:m),2));
out = int64(lo);
out(lo) = 1:nnz(lo);
out = out';

with kron

m = 7;
n = 6;

out = triu(kron(ones(ceil(n/2),ceil(m/2)),[1,0;0,1]));
out = out(1:n,1:m);
out(out~=0) = 1:nnz(out);
out = out';

Answer 2

[Kevin Phung]

Can you be more clear in what you are trying to do? Is this pattern supposed to go on? Or is this matrix A that you have provided exactly what you need, and you are looking for a way to programmatically create it rather than typing it out .