Removing elements of array by condition and without resizing?

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Jonathan Cardoza
Jonathan Cardoza el 19 de Feb. de 2019
Comentada: Jonathan Cardoza el 19 de Feb. de 2019
I'm trying to produce an array to later write into a .txt file. Currently, the array I am working with is a 5323x18 double. Due to the nature of its conception, roughly all the first 3-5 columns contain a non-zero numerical value, while the other columns (6-18) occasionally contains a non-zero numerical value. The rest of the elements of the array are zero. In order to ensure that the .txt file doesn't have any of these zeros, is there any way I can delete those elements from the array, while maintaining the array size?
For example, turning something like the following array:
[ 1 5 0 0 0 0
1 5 6 7 0 0
4 0 0 0 0 0
5 5 5 5 5 5]
to
[ 1 5
1 5 6 7
4
5 5 5 5 5 5]

Respuestas (1)

madhan ravi
madhan ravi el 19 de Feb. de 2019
Result=arrayfun(@(x)nonzeros(a(x,:)).',1:size(a,1),'un',0); % where a is your matrix
celldisp(Result)
  5 comentarios
madhan ravi
madhan ravi el 19 de Feb. de 2019
yes by holes I mean empty
Jonathan Cardoza
Jonathan Cardoza el 19 de Feb. de 2019
Ah, I see. I was hoping that the resultant combined row data in square brackets could be separated into their own cells.

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