Creating a matrix from a lagrer matrix

Hello everyone.

Please I need help in automatically dividing the matrix A below into three 5by 1 matrix.

A=[1
2
3
4
5
6
8
9
10
11
12
13
14
15]

Such that the first matrix created will be say

B=[1
2
3
4
5]

Thanks.

Answer 1

[Akira Agata]

How about the following?

In this case, C{1}, C{2}, ..., C{151} are 200-by-1 matrices each, extracted from original 30194-by-1 matrix.

% Sample 30194-by-1 data
A = rand(30194,1);

% Padding with "nan"
n = 200;
N = numel(A);
A = [A;nan(ceil(N/n)*n-N,1)];

% Divide A into 200-by-1 segments
C = mat2cell(A,repelem(n,ceil(N/n)));

[madhan ravi]

reshape() is much faster

[Benedict Egbon]

Hi Akira.

Thanks for the respone.

This actually worked well for me as desired.

Regards.

Answer 2

[Kevin Phung]

A = reshape(1:15,5,3); %reshaped into a 5x3 matrix.
B =A(:,1); %one of the column vectors that you desire

reading up on indexing can help:

https://www.mathworks.com/company/newsletters/articles/matrix-indexing-in-matlab.html

[Benedict Egbon]

Thank you very much for the response as this worked very well for this case.

At the moment, I have a 30194 by 1 matrix, and I want to make many 200 by 1 matrices from it.

Any suggestion on how to automate it, instead of doing B =A(:,1), C =A(:,2) etc.

Thanks.