Removing zeros from start of an array and inserting them at the end of same array

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Let say I have an array
A = [ 0 0 0 0 1 2 3 4 5 6 7 8 9 0 0 0 0 ]
I would like to know wheter is there any way to move starting four zeros to the end of same array A.
The result should be
Result = [ 1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 ]
Now, in this example there were only four zeros. I do have arrays which have more than 4 zeros.
Thanks

Accepted Answer

Alex Mcaulley
Alex Mcaulley on 13 Mar 2019
Try this:
A = [0 0 0 0 1 2 3 4 5 6 7 8 9 0 0 0 0];
idx = find(A>0,1);
B = [A(idx:end),zeros(1,idx-1)]
  3 Comments
Shahab Khan
Shahab Khan on 13 Mar 2019
Thank you, actually i figured that out myself so i deleted the question. But anyway Thanks alot.

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More Answers (2)

Matt J
Matt J on 13 Mar 2019
Edited: Matt J on 13 Mar 2019
n=find(A,1);
Result=circshift(A,1-n);

Sheng Chen
Sheng Chen on 13 Mar 2019
Try this
A = [ 0,1,0,3,12];
idx = 1;
for j = 1 : numel(A)
if A(j) ~= 0
% swap A(j) and A(idx)
A([j idx]) = A([idx j]);
idx = idx + 1;
end
end

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