Couldn't find what's wrong

a=cell(1,3)

a{2}= [2 4 5]

for i=1:3
    if numel(a{i})==3
        b=cellfun(@(q) q==a(i),a,'un',1)
    end
end

I tried to find index of the matrix which have a certain number of elements in a cell.

Answer 1

[madhan ravi]

q = 3;
b = find( cellfun( @numel, a ) == q )
%or
b = find( cellfun( 'prodofsize', a ) == q )

[IBM watson]

thanks but what is q=3 for ?

[madhan ravi]

Refers to number of elements you can change it accordig to your desire.