For loop question with matrix

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Gko K
Gko K el 23 de Mzo. de 2019
Comentada: Gko K el 25 de Mzo. de 2019
I have a matrix as below called A (60x3 double)
A = [10 3.5 -34.66
9 3.5 -35.6
8 3.5 -31.43
7 3.5 -29.04
6 3.5 -27.81
5 3.5 -26.59
4 3.5 -23.69
3 3.5 -16.47
2 3.5 2.94
1 3.5 24.03
5 3.5 25.86
4 3.5 35.98
3 3.5 55.89
2 3.5 91.82
1 3.5 101.5
6 3.5 -63.5
5 3.5 -67.03
4 3.5 -72.58
3 3.5 -80.98
2 3.5 -85.91
1 3.5 -63.15
7 3.5 -20.23
6 3.5 -19.92
5 3.5 -20.05
4 3.5 -19.69
3 3.5 -13.96
2 3.5 11.57
1 3.5 30.76
3 3.5 63.36
2 3.5 99.82
1 3.5 107.13
10 3.5 -47.09
9 3.5 -61.25
8 3.5 -61.89
7 3.5 -63.07
6 3.5 -65.29
5 3.5 -69.63
4 3.5 -76.96
3 3.5 -84.92
2 3.5 -80.39
1 3.5 -57.89]
I want to sum column 2 values until column 1 value is 1. I mean first sum must be on row 1 to row 10, and 2nd sum must be on row 15 to row 20, 3rd sum must be on row 21 to row 26 etc.
How can i do that with using for loop or another way?
  1 comentario
Adam Danz
Adam Danz el 23 de Mzo. de 2019
The number 1 is in the following rows of column 1:
>> find(A(:,1)==1)
ans =
10
15
21
28
31
41
so I'm having trouble figuring out what rule you're using to select row numbers.

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Respuestas (2)

Walter Roberson
Walter Roberson el 23 de Mzo. de 2019
locs = [find(A(:,1)==1); size(A,1)+1];
tsum = cumsum([0;A(:,2)]);
output = tsum(locs(2:end)) - tsum(locs(1:end-1));
  10 comentarios
Adam Danz
Adam Danz el 24 de Mzo. de 2019
Yeah, that was unclear to me from the beginning.
Gko K
Gko K el 24 de Mzo. de 2019
Editada: Gko K el 24 de Mzo. de 2019
Ok, thank you both, Sorry if i make you busy.
I have analysis results which are in a big excel table.
I want to split matrix as i show below:
My code runs true if i have 1 matrix. But i have a big table as shown in the pic.I want to run code for matrix 1 then matrix 2 then matrix 3 then matrix 4 then matrix 5 then matrix....n.
If you dont want to help no problem. Thanks for your previous helps friends.

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Adam Danz
Adam Danz el 24 de Mzo. de 2019
Editada: Adam Danz el 24 de Mzo. de 2019
"I want to sum column 2 values until column 1 value is 1."
With your input matrix "A", 's' is the sum of column 2 for each group.
% Create group numbers for each row
rowGroups = cumsum([0;A(1:end-1,1)] == 1)+1;
% Calculate sum of col 2 for each group
s = splitapply(@sum, A(:,2), rowGroups)
  5 comentarios
Adam Danz
Adam Danz el 24 de Mzo. de 2019
We've all been there.
Gko K
Gko K el 25 de Mzo. de 2019
Thank you

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