Conditional replacement of a vector of zeros and ones

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Hi All,
I have an array of zeros from 1:400 and want to randomly assign ones in 10 positions for every 40 zeros in the sequence.
cycles = 40;
count = 0;
state = zeros(1, 400);
for i = 1:cycles
tempstate = state(count:count+cycles)
for j = 1:10
tempstate(randi(numel(tempstate))) =1
end
count = count + 40
The issue I have is that I want wherever I assign a one to have a zero either side.
But still maintain 10 1's per 40 positions in the sequence.
Appreciate the help.
Thanks,
David

Accepted Answer

Andreas Bernatzky
Andreas Bernatzky on 4 Apr 2019
Edited: Andreas Bernatzky on 4 Apr 2019
Hey David,
this should do the Job. Sorry for my Variablenaming but I could not consider better names :)
sequence=40;
vectors2create=400/sequence;
amountofOnes=10;
finalVector=[];%end vector
for(a=1:1:vectors2create)
tempVec=zeros(1,40);
for(b=1:1:amountofOnes)
onePos(b)=randi(sequence,1);%determine the positions which become 1
end
tempVec(onePos)=1;%set the positions to 1
finalVector=[finalVector,tempVec];%append the final vector
end
  4 Comments
Andreas Bernatzky
Andreas Bernatzky on 4 Apr 2019
Should do the work now.
sequence=40;
vectors2create=400/sequence;
amountofOnes=10;
finalVector=[];%end vector
for(a=1:1:vectors2create)
tempVec=zeros(1,40);
onePos=[];
while(length(onePos)<amountofOnes)
tempPos=randi(sequence,1);%determine the positions which become 1
cAP=tempPos-1;%checkAscendingPos
cDP=tempPos+1;%checkDescendingPos
cOP=tempPos;%checkOwnPos
%if non of this position(or neighbouring) does appear in onePos this Position can be accepted
if(isempty(find(cAP==onePos))==1&&isempty(find(cDP==onePos))==1&&isempty(find(cOP==onePos))==1)
onePos(end+1)=tempPos;
end
end
tempVec(onePos)=1;%set the positions to 1
finalVector=[finalVector,tempVec];%append the final vector
end

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