Contourf: fill inside instead of outside
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    Marco Sammito
 el 7 de Abr. de 2019
  
    
    
    
    
    Comentada: DGM
      
      
 el 26 de Jul. de 2024
            Hi, how can I fill the area within the circle? At the moment Matlab fills the area outside. I would like the outside to be white and the inside to be filled. Thanks.
relamdt=-4:0.1:4;
imlamdt=-4:0.1:4;
[x,y]=meshgrid(relamdt,imlamdt);
axis square;
lamdt=x+i*y;
sig = (1 + lamdt);
v = [1,1];
contourf(x,y,abs(sig),v)

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Respuesta aceptada
  Walter Roberson
      
      
 el 8 de Abr. de 2019
        
      Editada: Walter Roberson
      
      
 el 8 de Abr. de 2019
  
      contourf(x, y, -abs(sig), -v)
Alternately, possibly
[~,h] = contourf(x, y, abs(sig), v);
drawnow();     %seems to be needed to get NodeChildren created
bg = h.NodeChildren(2).ColorData;
h.NodeChildren(2).ColorData = uint8([255; 255; 255; 255]);
ax = ancestor(h,'axes');
ax.Color = bg;
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Más respuestas (2)
  David Wilson
      
 el 8 de Abr. de 2019
        A quick hack (following the essence of your code) is
cmap = colormap; cmap(end,:) = [1,1,1]; colormap(cmap); 
contourf(x,y,abs(sig),[0,1]);
axis square
  Roberto Tumolo
      
 el 26 de Jul. de 2024
        What if one wants to extract the values shown inside and outside (suppose you don't know them because they come from a contour? 
1 comentario
  DGM
      
      
 el 26 de Jul. de 2024
				The way the question is posed makes it unclear what information we might have.  From a contour()/contourf() object, we can know a set of discrete z-values associated with the given level curves, but unless we have access to the original zdata, we don't know the actual values between the level curves. If we don't have access to the object itself (e.g. if all we have is a saved figure as a raster image (a screenshot)), then things get more restricted.
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