How do I plot the bode plot of the transfer function with exp(sT)?

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yklu008
yklu008 el 6 de Mayo de 2019
Respondida: Raj el 6 de Mayo de 2019
The transfer function is show as following, where T=10e-9.
How could I get the bodeplot from this function?
59538682_243684739829449_8500004122919960576_n.jpg
  1 comentario
David Wilson
David Wilson el 6 de Mayo de 2019
Since you have the time delay element in the denominator, your don't have a polynomial transfer function anymore, so you will need to approximate it using pade.
You also might want to check that it is exp(-Ts), not the acausal version you have written above.

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Raj
Raj el 6 de Mayo de 2019
You can rearrange the equation as (e^-sT)(s+10)/s(1-(e^-sT))
Then your code should look something like this:
s = tf('s');
T=10e-9;
f = exp(-T*s);
sys=(f*(s+10))/(s*(1-f))
bode(sys)

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