MATLAB Answers

What's the best way to shorten this?

1 view (last 30 days)
Hans123
Hans123 on 9 May 2019
Commented: Adam Danz on 13 May 2019
This is a very lengthy code for something repetitive, I want to know whether there is a simpler, more efficient way of doing this.
The purpose of the code is to load text files and trim them according to the same criteria and check which one is the shortest and use the shortest length in calculations that happen later in the code.
T1 = dlmread("Trial 1");
T2 = dlmread("Trial 2");
T3 = dlmread("Trial 3");
T4 = dlmread("Trial 4");
T5 = dlmread("Trial 5");
T6 = dlmread("Trial 6");
T7 = dlmread("Trial 7");
T8 = dlmread("Trial 8");
T9 = dlmread("Trial 9");
T10 = dlmread("Trial 10");
%removal of unwanted elements from the raw data array
T1(T1(:,11)<=0 ,:) = [];
T1(T1(:,3)==25 ,:) = [];
T1(T1(:,3)<500 ,:) = [];
T1(T1(:,5)==0 ,:)= [];
T1(find(T1(:,12)>780,1):end, :) = [];
T2(T2(:,11)<=0 ,:) = [];
T2(T2(:,3)==25 ,:) = [];
T2(T2(:,3)<500 ,:) = [];
T2(T2(:,5)==0 ,:)= [];
T2(find(T2(:,12)>780,1):end, :) = [];
T2(T2(:,11)<=0 ,:) = [];
T3(T3(:,3)==25 ,:) = [];
T3(T3(:,3)<500 ,:) = [];
T3(T3(:,5)==0 ,:)= [];
T3(find(T3(:,12)>780,1):end, :) = [];
T4(T4(:,11)<=0 ,:) = [];
T4(T4(:,3)==25 ,:) = [];
T4(T4(:,3)<500 ,:) = [];
T4(T4(:,5)==0 ,:)= [];
T4(find(T4(:,12)>780,1):end, :) = [];
T5(T5(:,11)<=0 ,:) = [];
T5(T5(:,3)==25 ,:) = [];
T5(T5(:,3)<500 ,:) = [];
T5(T5(:,5)==0 ,:)= [];
T5(find(T5(:,12)>780,1):end, :) = [];
T6(T6(:,11)<=0 ,:) = [];
T6(T6(:,3)==25 ,:) = [];
T6(T6(:,3)<500 ,:) = [];
T6(T6(:,5)==0 ,:)= [];
T6(find(T6(:,12)>780,1):end, :) = [];
T7(T7(:,11)<=0 ,:) = [];
T7(T7(:,3)==25 ,:) = [];
T7(T7(:,3)<500 ,:) = [];
T7(T7(:,5)==0 ,:)= [];
T7(find(T5(:,12)>780,1):end, :) = [];
T8(T8(:,11)<=0 ,:) = [];
T8(T8(:,3)==25 ,:) = [];
T8(T8(:,3)<500 ,:) = [];
T8(T8(:,5)==0 ,:)= [];
T8(find(T8(:,12)>780,1):end, :) = [];
T9(T9(:,11)<=0 ,:) = [];
T9(T9(:,3)==25 ,:) = [];
T9(T9(:,3)<500 ,:) = [];
T9(T9(:,5)==0 ,:)= [];
T9(find(T9(:,12)>780,1):end, :) = [];
T10(T10(:,11)<=0 ,:) = [];
T10(T10(:,3)==25 ,:) = [];
T10(T10(:,3)<500 ,:) = [];
T10(T10(:,5)==0 ,:)= [];
T10(find(T10(:,12)>780,1):end, :) = [];
L1=length(T1);
L2=length(T2);
L3=length(T3);
L4=length(T4);
L5=length(T5);
L6=length(T6);
L7=length(T7);
L8=length(T8);
L9=length(T9);
L10=length(T10);
Lmin = min([L1(:);L2(:);L3(:);L4(:);L5(:);L6(:);L7(:);L8(:);L9(:);L10(:)]);

  3 Comments

John D'Errico
John D'Errico on 9 May 2019
Can I suggest this is why creating those numbered variables is such a terrible idea? Instead, learn to use arrays. A cell array, for example, would make it trivial to write the entire mess in one trivial to write (and short) for loop.
Stephen Cobeldick
Stephen Cobeldick on 13 May 2019
Using numbered variables is a sign that you are doing something wrong.
Copy-and-pasting code is a sign that you are doing something wrong.
Remember that computers are only really good at one thing: repeatedly doing simple tasks. So when you find yourself copy-and-pasting the same code over and over again, then you are just doing the computer's job for it. Instead get the computer to do it for you: use a loop.
Hans123
Hans123 on 13 May 2019
thank you for your inputs, I really appreciate it!

Sign in to comment.

Accepted Answer

Adam Danz
Adam Danz on 9 May 2019
Edited: Adam Danz on 13 May 2019
This should get you started but it's not tested and there will likely be some kinks to work out. I'd be glad to help more if needed.
trials = ["Trial 1", "Trial 2", "Trial 3", "Trial 4", "Trial 5", ...
"Trial 6", "Trial 7", "Trial 8", "Trial 9", "Trial 10" ];
nTrials = numel(trials);
T = cell(size(trials));
for i = 1:nTrials
T{i} = dlmread(trials(i));
%removal of unwanted elements from the raw data array
T{i}(T{i}(:,11)<=0 ,:) = [];
T{i}(T{i}(:,3)<500 ,:) = [];
T{i}(T{i}(:,5)==0 ,:)= [];
T{i}(find(T{i}(:,12)>780,1):end, :) = [];
end
L = cellfun(@length, T,'UniformOutput', false);
Lmin = min([L{:}]);

  2 Comments

Hans123
Hans123 on 13 May 2019
this works perfectly, I really appreciate the help. I am relatively new to MATLAB and cell functions as well. I didn't quite understand how this line works
L = cellfun(@length, T,'UniformOutput', false);
Any help would be appreciated.
Cheers
Adam Danz
Adam Danz on 13 May 2019
The first input to cellfun() is a function handle. The second input is a cell array. The cellfun() function applies the function in input #1 to each element of the cell array in input #2. For example, the cell array T (defined below) has 4 elements. The length of the four elements are [3, 4, 5, 2].
T = { [1 2 3], [1 2 3 4], [1 2 3 4 5], [1 2] };
The 'UniformOutput' flag specifies that the output should be stored in a cell array.

Sign in to comment.

More Answers (1)

Sign in to answer this question.

Tags


Translated by