How to remove the duplicate in the cell array but still keep the array structure?

A={[3 11];[6 5 8];[ 11 5];[5]};

I wonder if there is any way to remove the duplicate numbers in A but still keep the dimension of the cell array? like

A={[3 11];[6 5 8];[];[]};

appreciate your time!

[Kevin Phung]

how did

A={[3 11];[6 5 8];[ 11 5];[5]};

become

A={[3 11];[6 5 8];[];[]};

[Hang Vu]

Yes, that is my question! i want to keep the structure

[Jan]

@Hang Vu: You forgot to explain, which operation you want to apply. Why does "remove the duplicate in the cell array" produce the output for the shown input? Let me guess:

If a number occurs in an element of the cell, remove it from all subsequent elements.

Answer 1

[Jan]

A = {[3 11];[6 5 8];[ 11 5];[5]};
for iA = 1:numel(A)
    a = A{iA};
    for jA = iA + 1:numel(A)
        A{jA} = A{jA}(~ismember(A{jA}, a));
    end
end

Or:

list = A{1};
for iA = 2:numel(A)
   A{iA} = A{iA}(~ismember(A{iA}, list));
   list  = union(list, A{iA})
end

[Hang Vu]

Thank you Jan!