Info

La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.

solve runge kutta method

1 visualización (últimos 30 días)
Mariam Gasra
Mariam Gasra el 15 de Mayo de 2019
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
lamda=0.2;
mu=0.8;
h=0.1; % step size
x = 0:h:5; % Calculates upto y(3)
Y = zeros(1,length(x));
y(1) = 0.2; % redo with other choices here.
% initial condition
%F_xy = @(??,??) (lamda^2/(lamda+mu)^2)*exp(-2(lamda+mu)*t)+((2*mu*lamda)/(lamda+mu)^2)*exp(-(mu+lamda)*t)+mu^2/(lamda+mu)^2;
for i=1:(length(x)-1) % calculation loop
k_1 = F_xy(x(i),y(i));
k_2 = F_xy(x(i)+0.5*h,y(i)+0.5*h*k_1);
k_3 = F_xy((x(i)+0.5*h),(y(i)+0.5*h*k_2));
k_4 = F_xy((x(i)+h),(y(i)+k_3*h));
y(i+1) = y(i) + (1/6)*(k_1+2*k_2+2*k_3+k_4)*h; % main equation
end
% validate using a decent ODE integrator
tspan = [0,5]; y0 = -0.5;
[tx, yx] = ode45(F_xy, tspan, y0)
plot(x,y,'o-', tx, yx, '--')
if i have this equation F_xy=(lamda^2/(lamda+mu)^2)*exp(-2(lamda+mu)*t)+((2*mu*lamda)/(lamda+mu)^2)*exp(-(mu+lamda)*t)+mu^2/(lamda+mu)^2
the variable only t
how can correct the code to get the answer?
  1 comentario
James Tursa
James Tursa el 15 de Mayo de 2019
Editada: James Tursa el 15 de Mayo de 2019
Can you show the code you are using for the F_xy function? Can you post the original DE you are trying to solve?

Respuestas (0)

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by