Find the earliest common date and indicator of two date vectors.

Hi,
I have got two date vectors: a=[28.02.2019;01.03.2019;04.03.2019;...] and b=[01.03.2019;04.03.2019;...]
How to find the earliest common date (=01.03.2019) and its vector index indicator (for date vector a is 2 and b is 1).
Thank you in advance for any suggestions.

2 comentarios

"I have got two date vectors"
Please use valid matlab syntax for your examples.
In matlab a date vector is a 1x3 or 1x6 vector containing only 1 date.
a = [28.02.2019; 01.03.2019; 04.03.2019];
is not valid matlab syntax. So what do you have?
Thank you for your code suggestion.
I have got a 55x1 datetime date vector which is vector A and a 56x1 datetime date vector which is vector B.
The date format is 06-Mar-2019
----
It does not have to be that the time vector A is always smaller than Vector B. It can change. It can also be that the first date of time vector A begins later than in date vector B. It must be flexible.

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 Respuesta aceptada

intersect will give you all the dates common to a and b. By default, it also sorts them, so the first of these will be the earliest one, so:
[commondates, whereina, whereinb] = intersect(a, b);
firstcommon = commondates(1);
whereina = whereina(1);
whereinb = whereinb(1);

Más respuestas (1)

Rik
Rik el 17 de Mayo de 2019
Editada: Rik el 17 de Mayo de 2019
This answer assumes you have your dates in a datetime format. If you don't it should be relatively easy to convert to it. If your release is too old to support it, please comment with what release you're using.
a=datetime([2019 2019 2019],[2 3 3],[28 1 4]);
b=datetime([2019 2019 2019],[3 3 5],[1 4 1]);
[common_dates,ind_in_a]=ismember(a,b);
common_dates=a(common_dates);
[first,a_min_ind]=min(common_dates);
a_ind=find(ind_in_a==a_min_ind);
b_ind=find(b==first);

4 comentarios

Thank you for code. As I mentioned above, it is not for all cases valid. see my comments above.
For what cases doesn't this work? This code does not assume equal length of the vector. It works for most shapes that have no zero-length dimension.
BdS
BdS el 17 de Mayo de 2019
Editada: Guillaume el 17 de Mayo de 2019
With your code I get for a the indicator 1 and for b 1 as well.
I should actually get for a indicator 2 and b indicator 1. Both indicates 01-Mar-2019 in vector a and b.
The code should also work in cases when b begins with an earlier date.
I edited my answer. It works now, but it has become messy, so I would suggest you keep using Guillaume's solution.

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Preguntada:

BdS
el 17 de Mayo de 2019

Comentada:

Rik
el 17 de Mayo de 2019

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