Why do i get a blank graph?
11 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
jpmontoya
el 1 de Jun. de 2019
Comentada: jpmontoya
el 2 de Jun. de 2019
Hello, as you can see in the code below I am trying to make two plots but the problem is that the subplot (2,1,2) goes blank. I got nothing. I think maybe there is something wrong with the variables k1 and v1 since they depend on X(1) and X(3) which come from the solution of an ODE. Can somebody help me? Thanks in advance.
function [T,X] = call_osc()
tspan = [0 2000];
x1_0=0.05;
x2_0=0.05;
x3_0=298.15;
x4_0=0.1;
odeset('RelTol', 1e-10, 'AbsTol', 1e-12);
[T,X]=ode15s(@osc,tspan,[x1_0 x2_0 x3_0 x4_0]);
R=8.314;
Ea1=80000;
alpha=11;
A=1;
k1= 0.8*exp(-Ea1/(alpha*R*X(3)));
v1=k1*A*X(1);
subplot(2,1,1)
plot(T,X(:,3))
grid on
xlabel('tiempo(s)','Fontsize',13,'FontWeight','Bold')
ylabel('Temperatura (K)','Fontsize',13,'FontWeight','Bold')
subplot(2,1,2)
plot(X(:,1),v1)
grid on
end
1 comentario
Respuesta aceptada
gonzalo Mier
el 2 de Jun. de 2019
Editada: gonzalo Mier
el 2 de Jun. de 2019
You are computing v1 as
k1= 0.8*exp(-Ea1/(alpha*R*X(3)));
v1=k1*A*X(1);
v1 is a matriz of size 1x1. So when you do plot( "vector of size 1xn" , "cte" ) the output is an empty plot.
Check if the way to compute v1 is correct or you have to use X(:,1).
PD: You also can check this doing:
plot(X(:,1),v1,'*')
3 comentarios
Walter Roberson
el 2 de Jun. de 2019
tspan = [0 2000];
[T,X]=ode15s(@osc,tspan,[x1_0 x2_0 x3_0 x4_0]);
X will be output as something with an unpredictable number of rows, and 4 columns.
k1= 0.8*exp(-Ea1/(alpha*R*X(3)));
v1=k1*A*X(1);
X is a 2D array. X(1) and X(3) are linear indexing, so X(3) is X(3,1) ans X(1) is X(1,1) . X(1,1) should be the same as x1_0 but X(3,1) will be the x1 output at the third time point, whatever the third time point happens to be.
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!