Multiply Image Pixels by a Matrix

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Royi Avital
Royi Avital el 22 de Ag. de 2012
Hello, Let's say I have a 3 channel image M -> [numRowx * numColumns * numChannels]. I also have a 3 by 3 matrix A (Color Conbersion).
I would like to multiply each pixel 3 channel by the matrix to have a new 3 channels pixel.
How would you do that the most efficient way without writing the actual formula by hand (Multiplying each channel of the image by a row)?
My best so far is:
rgbToYPbPrMat = [0.299, 0.587, 0.144; 0.5, -0.419, -0.081; -0.169, -0.331, 0.5];
yPbPrToRgbMat = inv(rgbToYPbPrMat);
inputImage = randi([0, 255], [256, 256, 3], 'uint8');
inputImageFP = double(inputImage) / 255; %<! Floating Point
figure;
image(inputImage);
axis image;
inputImageYPbPrFP = shiftdim(reshape((rgbToYPbPrMat * reshape(shiftdim(inputImageFP, 2), [3, (256 * 256)])), [3, 256, 256]), 1);
Thanks.
  3 comentarios
Royi Avital
Royi Avital el 22 de Ag. de 2012
Hi @Sean, Look at my code I added.
I couldn't make it work with 'bsxfun'.
Royi Avital
Royi Avital el 23 de Ag. de 2012
Anyone? Please...

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Jan
Jan el 23 de Ag. de 2012
I cannot check it currently, but please try:
M = rand(numRows, numColumns, 3);
T = rand(3, 3);
P = reshape(M, numRows * numColumns, 3) * T';
Result = reshape(P, numRows, numColumns, 3);
  1 comentario
Royi Avital
Royi Avital el 23 de Ag. de 2012
Hi, Checked it, it does work and it the fastest so far (Since the Transpose works on the smaller matrix).
Do you think there's even a faster way?
Thanks.

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