How to plot an integral

Hello!

I need some help plotting the following:

This is what I have:

syms x
kw = 91371;
CaO= 1.81*10^(-4);
FaO= 0.1233;
K = 1.29;
fun =FaO*((1+K*CaO*(1-x))/(kw*CaO*(1-x)))
W=int(fun);
fplot(W,[0 1

But nothing comes out on the graph. I want to plot W on the Y-axis and x on the X-axis, between 0 and 1 (because it's a conversion in chemistry).

Does anyone know what I'm doing wrong?

[KALYAN ACHARJYA]

Same question

https://in.mathworks.com/matlabcentral/answers/467252-matlab-code-to-solve-an-integral

W=int(fun);
fplot(W,[0 1])

[Marina Gonzalez]

Same question because it doesn't work.

I obviously forgot the final parenthesis when I copied it.

Why doesn't it show on the graph? This is what I get when I plot it:

[KALYAN ACHARJYA]

Actually, at present I dont have Matlab,therfore unable test it pls show int(fun) expression?

[Marina Gonzalez]

Sure!

W =
 
(10621383255117913671*x)/6101500778987273584640000 - (2711395674095616*log(x - 1))/363677786528305625

[Walter Roberson]

In this calculation W is imaginary below 2.0007245246191665436401515314702

Answer 1

[Star Strider]

‘But nothing comes out on the graph.’

The result of the int function is a constant. At best, you will get a straight line.

I am not certain what you want. You can get it to plot as a function of the upper limit of integration by creating a function from it:

syms x a 
kw = 91371;
CaO= 1.81*10^(-4);
FaO= 0.1233;
K = 1.29;

fun = FaO*((1+K*CaO*(1-x))/(kw*CaO*(1-x)));
W(a) = int(fun, x, 0, a);

fplot(W,[0 1])