Clustering Calculating total value

1 visualización (últimos 30 días)
Jess
Jess el 20 de Jun. de 2019
Comentada: Walter Roberson el 21 de Jun. de 2019
Sir
I have an Input matrix 90X2 matrix and another matrix C 4005X4 .
The following steps need to be performed
  1. Initially I have to select the (1,1) value and (1,2) value of C and store it in C1(1x2 matrix)
  2. Next I have to select the (1,3) value and (1,4) value of C and store it in C2 (1x2 matrix)
  3. Next I have to find the difference between each row of the matrix and C1 and store it in X(90x2 matrix)
  4. Next I have to find the difference between each row of the matrix and C2 and store it in Y (90x2 matrix
  5. Then I have to add the row values of X and store it in A(90x1 matrix)
  6. Then I have to add the row values of Y and store it in B((90x1 matrix)
  7. Then I have to compare the values of A and B. If A is greater, then number 2 should be stored in matrix Z and the smaller number among A and B should be stored in matrix M, else number 1 should be stored in matrix Z and the smaller number among A and B should be stored in matrix M. Now we have got an 90x1 Z matrix with values of either 1 or 2 and a 90x1 P matrix with the smaller values among A and B.
  8. Now I have to find the sum of all values of M and store it in P.
  9. Next I have to carry out the same procedure with the value of (2,1) and (2,2) as C1 and (2,3) and (2,4) as C2.
  10. Likewise I have to carry out the operation for all 4005 values of C
  11. Finally I have to find the value of C1 and C2 for which the value of P is minimum
Kindly help me with this

Respuestas (1)

Walter Roberson
Walter Roberson el 20 de Jun. de 2019
C1 = C(1,1:2);
C2 = C(1, 3:4);
X = YourArray - C1;
  2 comentarios
Jess
Jess el 21 de Jun. de 2019
Sir
I have to do it for all the 4005 combinations
How to do it?
Plz help
Walter Roberson
Walter Roberson el 21 de Jun. de 2019
for loop. Possibly using a cell array.

Iniciar sesión para comentar.

Categorías

Más información sobre Shifting and Sorting Matrices en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by