Change of surface in a rectangular tank

1 visualización (últimos 30 días)
MOUNIBA REDAH
MOUNIBA REDAH el 29 de Jun. de 2019
Respondida: darova el 30 de Jun. de 2019
I am plotting a change of surface in terms of beta
The thing is I see no change in the figure when I change the values of beta
Can you help me please
here is the code
clear
x=pi
x0=0.05;
omega=3;
beta0=0.1;
g=10;
z0=(1-(beta0*g)*omega^(-2))^0.5;
h=1;
b=4*(omega^(2))*x0*(g*pi)^(-1)
h=1;
g=10 ;
N=2;
syms t x z0
z0=0;
for n=0:N;
Z=((2*n+1)^(-2))*cos((2*n+1)*x)*cosh(z0*(2*n+1)*((cosh((2*n+1)*z0*h)-g*(2*n+1)*sinh((2*n+1)*z0*h)*(pi^(2)*z0)^(-1))^(-1)))*sin(t);
Zf=z0+Z;
end
Z=simplify(Zf);
Z1=subs(Z,x,pi);
t=0:0.02:20;
x=0:0.02:pi;
[T,X]=meshgrid (t,x);
for n=0:N;
Z=((2*n+1)^(-2))*cos((2*n+1).*X)*cosh(z0*(2*n+1)*((cosh((2*n+1)*z0*h)-g*(2*n+1)*sinh((2*n+1*z0)*h)*(pi^(2)*z0)^(-1))^(-1))).*sin(T);
Zf=z0+Z;
end
a=(omega^(2))*x0*(X-0.5*pi)*g^(-1);
Z=a.*sin(T)+b*Z;
mesh(T,X,Z)
grid on
title('evolution spaciotemporelle de la surface libre');

Respuesta aceptada

darova
darova el 30 de Jun. de 2019
I suggest you to clarify your code. There are some errors i think
x=pi
x0=0.05;
omega=3;
beta0=0.1;
g=10;
z0=(1-(beta0*g)*omega^(-2))^0.5;
h=1;
b=4*(omega^(2))*x0*(g*pi)^(-1)
h=1; % again
g=10 ; % declaring the same variable
N=2;
syms t x z0 % declaring symbolic variable
% and re-write them?
z0=0; % re-write z0? It's symbolic
for n=0:N;
Z=((2*n+1)^(-2))*cos((2*n+1)*x)*cosh(z0*(2*n+1)*((cosh((2*n+1)*z0*h)-g*(2*n+1)*sinh((2*n+1)*z0*h)*(pi^(2)*z0)^(-1))^(-1)))*sin(t);
Zf=z0+Z; % you mean Zf=Zf+Z ?
end
Z=simplify(Zf);
Z1=subs(Z,x,pi); % substitute only x variable (t remains)
t=0:0.02:20;
x=0:0.02:pi;
[T,X]=meshgrid (t,x);
for n=0:N;
% overwrite Z variable? Z has some value already
Z=((2*n+1)^(-2))*cos((2*n+1).*X)*cosh(z0*(2*n+1)*((cosh((2*n+1)*z0*h)-g*(2*n+1)*sinh((2*n+1*z0)*h)*(pi^(2)*z0)^(-1))^(-1))).*sin(T);
Zf=z0+Z;
end
Pay attention to warnings
Untitled.png

Más respuestas (0)

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by