Finding the Probability of a Sequence of Numbers

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Aragorn23
Aragorn23 el 16 de Jul. de 2019
Respondida: Bruno Luong el 16 de Jul. de 2019
Hi everyone,
I have a vector with data varying from 1 to 120.
A= [10 13 10 1 111 102 10 13 7 10 112 100 14 116 102 10 14 120].
I would like to calculate, the probability' sequence of each number (e.g., probability of the number 1 be followed by the number 111; probability of the number 14 be followed by the number 116, etc ...)?
How can I do that?
Thanks.
  3 comentarios
Adam
Adam el 16 de Jul. de 2019
Sounds like you would need to build a 120x120 matrix of occurences of each number followed by each other number (something I guess I would use a for loop to do, at least initially) and then work out probabilities from the sum of each row in the table. It's a very small sample to do any kind of probability analysis on though. I assume this is just an example and your real data is bigger?
Aragorn23
Aragorn23 el 16 de Jul. de 2019
You're right, it's just a small sample.

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 16 de Jul. de 2019
Editada: Walter Roberson el 16 de Jul. de 2019
A= [10 13 10 1 111 102 10 13 7 10 112 100 14 116 102 10 14 120];
Ac = A.';
counts = accumarray([Ac(1:end-1), Ac(2:end)], 1, [120 120], [], [], true);
probs = counts ./ max(1, sum(counts,2));
[c, r, s] = find(probs.');
[r, c, s]

Más respuestas (1)

Bruno Luong
Bruno Luong el 16 de Jul. de 2019
N = histcounts2(A(1:end-1),A(2:end),1:121,1:121);
p = N / sum(N(:))

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