obtaining the average value for a data set
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Hello, I have a data set which contains a value for a number of stations during some years (station, date, value). Data for some days is missing. I need to create a column with annual average value per station. I appreciate your help.
station date value average(yearly per station)
1 2001/1/1 2 2
1 2001/1/3 1 2
1 2001/1/5 3 2
2 2001/1/1 2 2.5
2 2001/1/4 3 2.5
1 2002/1/2 2 1.5
1 2002/1/6 1 1.5
2 2002/1/1 2 2.5
2 2002/1/2 3 2.5 . .
3 comentarios
Matt Fig
el 4 de Sept. de 2012
It looks more like (station, date, value, value) to me. Can you tell us what form this data is in (i.e., cell array, Excel sheet, etc.) and what to do with the extra value?
Azzi Abdelmalek
el 4 de Sept. de 2012
Editada: Azzi Abdelmalek
el 4 de Sept. de 2012
can you specify the size of your data array, cell or .., how should the result looks like?
FATEMEH
el 4 de Sept. de 2012
Respuestas (1)
Matt Tearle
el 4 de Sept. de 2012
Editada: Matt Tearle
el 4 de Sept. de 2012
It looks like the fourth column is what you want to calculate. If so, this will do the job, assuming that you have the first three columns as station, date, and value (numeric vectors except date which is a cell array of strings)
% get the years from the date strings
dv = datevec(date);
year = dv(:,1);
% get all combinations of station & year
[stlist,yrlist] = meshgrid(unique(station),unique(year));
% allocate space for the calculated average
avg = zeros(size(station));
% loop over every station/year combination
for k = 1:numel(stlist)
% find the location of this combination in the data set
idx = (year == yrlist(k)) & (station == stlist(k));
% calculate the mean
avg(idx) = mean(value(idx));
end
This could probably be simplified with prior knowledge of the station numbers and years.
EDIT TO ADD: Given your comment above, ignore the first couple of lines -- you already have year.
3 comentarios
FATEMEH
el 6 de Sept. de 2012
Sean de Wolski
el 6 de Sept. de 2012
Why would you want to avoid the loop? The loop will likely be very fast and is easy to read/understand.
Matt Tearle
el 6 de Sept. de 2012
Possibly, although I doubt it will be neat. More importantly, why do you want to avoid loops?
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