How to write this in matlab?

How to write this equation in matlab?

f (xn) = x(n+1) = x(n)/a for 0 ≤ x(n) ≤ a

1−x(n)/1−a a ≤ x(n) ≤ 1

Where x0 is the initial value and xn ∈ [0,1]. The control parameter a ∈ (0,1) and when a is not equal to 0.5, system enters a chaotic state.

Answer 1

[Rik]

Because of the recursion limit (and other factors), it is smarter to implement this in a loop, instead of a recursive function.

The code below has some assumptions about your function you should check, but it shows the general idea.

x0=0.1;
N=30;
a=0.4;

x=zeros(N,1);
x(1)=x0;
for n=1:(N-1)
    if 0<=x(n) && x(n)<a
        x(n+1)= x(n)/a;
    else
        x(n+1)= (1-x(n))/(1-a);
    end
end

[darova]

Please use tabs to maek your code more readable

for n=1:(N-1)
    if 0<=x(n) && x(n)<a
        x(n+1)= x(n)/a;
    else
        x(n+1)= (1-x(n))/(1-a);
    end
end

[Rik]

I'm on mobile so formatting is very annoying and time consuming.

If anyone with editing privileges sees this, feel free to edit. Otherwise I might fix it in a few days.

[Fawad Masood]

x=zeros(N,1);??????????????????????????????

[Rik]

Eloquently put. What don't you understand about that line?

[Adam Danz]

@Fawrad, X = zeros(sz1,...,szN) check out that link.